## PEC EPE Exam Numerical Questions for Civil / Transportation Engineering

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### Other PEC EPE Exam Past Paper Questions

**A vehicle travels a distance of 240 km in 4 hours. What is its average speed?**

Solution:

Average speed = Total distance / Total time

Average speed = 240 km / 4 hours

Average speed = 60 km/h

**A bus starts from a station and travels at an average speed of 40 km/h for 2 hours. It then increases its speed to 60 km/h for the next 3 hours. What is the total distance covered by the bus?**

Solution:

Distance covered in the first 2 hours = 40 km/h * 2 hours = 80 km

Distance covered in the next 3 hours = 60 km/h * 3 hours = 180 km

Total distance covered = 80 km + 180 km = 260 km

**The traffic flow on a highway is measured as 1500 vehicles per hour. If the average vehicle length is 5 meters, what is the flow rate in vehicles per minute?**

Solution:

Flow rate in vehicles per minute = Traffic flow in vehicles per hour / 60

Flow rate in vehicles per minute = 1500 vehicles per hour / 60 = 25 vehicles per minute

**A freight train takes 3 minutes to pass completely through a tunnel. If the length of the train is 250 meters, what is the speed of the train?**

Solution:

Speed = Distance / Time

Speed = 250 meters / 3 minutes = 83.33 meters per minute

**The stopping sight distance for a vehicle traveling at 60 km/h is 60 meters. If the perception-reaction time of the driver is 2 seconds, what is the total stopping distance for the vehicle?**

Solution:

Total stopping distance = Perception-reaction distance + Braking distance

Perception-reaction distance = (Perception-reaction time) * (Speed in m/s)

Perception-reaction distance = 2 seconds * (60 km/h * 1000 m/km) / (3600 s/h) = 33.33 meters

Braking distance = Stopping sight distance – Perception-reaction distance

Braking distance = 60 meters – 33.33 meters = 26.67 meters

Total stopping distance = 33.33 meters + 26.67 meters = 60 meters

**A traffic signal operates with a cycle length of 120 seconds. If the green time for a particular movement is 40 seconds, what is the time for which this movement is stopped (red time)?**

Solution:

Red time = Cycle length – Green time

Red time = 120 seconds – 40 seconds = 80 seconds

**A city has a total road network of 800 kilometers and an annual traffic growth rate of 5%. What is the increase in road length after 4 years?**

Solution:

Increase in road length = Initial road length * (Growth rate/100) * Number of years

Increase in road length = 800 km * (5/100) * 4 years = 160 km

**The annual average daily traffic (AADT) on a highway is 10,000 vehicles. If the design period is 20 years and the traffic growth rate is 3% per year, what will be the traffic volume after 20 years?**

Solution:

Traffic volume after 20 years = AADT * (1 + Growth rate/10e0)^Number of years

Traffic volume after 20 years = 10,000 * (1 + 3/100)^20 โ 18,061 vehicles

**A road has a width of 7 meters and consists of two lanes. If each lane has a width of 3.5 meters, what is the total paved area of the road (excluding shoulders) for a length of 2 kilometers?**

Solution:

Total paved area = Road width * Length

Total paved area = (2 lanes * 3.5 meters) * 2000 meters = 14,000 square meters

**The traffic flow on a road segment is measured as 800 vehicles per hour. If the average headway (time gap between consecutive vehicles) is 5 seconds, what is the flow rate in vehicles per second?**

Solution:

Flow rate in vehicles per second = Traffic flow in vehicles per hour / 3600

Flow rate in vehicles per second = 800 vehicles per hour / 3600 = 0.22 vehicles per second

**A traffic signal at an intersection has a cycle length of 120 seconds. The green time for the main road is 40 seconds, and the green time for the left-turn movement is 30 seconds. Calculate the total lost time at the intersection.**

Solution:

Total lost time = Cycle length – (Green time for main road + Green time for left-turn movement)

Total lost time = 120 seconds – (40 seconds + 30 seconds) = 50 seconds

**The width of a two-lane highway is 7 meters, and each lane has a width of 3.5 meters. If the shoulder width on each side is 1 meter, calculate the total width of the road including the shoulders.**

Solution:

Total width of the road = (Width of two lanes + Shoulder width on one side + Shoulder width on the other side)

Total width of the road = (2 lanes * 3.5 meters) + (1 meter + 1 meter) = 9 meters

**The sight distance required for a vehicle traveling at 80 km/h is 100 meters. If the perception-reaction time of the driver is 2 seconds, calculate the stopping distance for the vehicle.**

Solution:

Stopping distance = Sight distance required + Perception-reaction distance

Perception-reaction distance = (Perception-reaction time) * (Speed in m/s)

Perception-reaction distance = 2 seconds * (80 km/h * 1000 m/km) / (3600 s/h) โ 44.44 meters

Stopping distance = 100 meters + 44.44 meters โ 144.44 meters

**A road segment has a traffic flow rate of 1,200 vehicles per hour. If the average headway (time gap between consecutive vehicles) is 5 seconds, calculate the speed at which the vehicles are traveling.**

Solution:

Speed = Distance / Time

Distance = Length of each vehicle

Time = Average headway = 5 seconds

Speed = Length of each vehicle / Average headway

Speed = 5 meters / 5 seconds = 1 meter per second

**A bus travels at an average speed of 50 km/h for a distance of 200 kilometers. Calculate the travel time for the bus.**

Solution:

Travel time = Distance / Average speed

Travel time = 200 km / 50 km/h = 4 hours

**The demand for a transportation service is 1,500 trips per day. If the service operates for 16 hours per day, calculate the average flow rate of trips per hour.**

Solution:

Average flow rate = Demand / Operating hours per day

Average flow rate = 1,500 trips / 16 hours = 93.75 trips per hour

**The critical headway for a traffic signal is 5 seconds. If the saturation flow rate at the intersection is 1,800 vehicles per hour, calculate the cycle length of the traffic signal.**

Solution:

Cycle length = Critical headway * Saturation flow rate

Cycle length = 5 seconds * (1,800 vehicles per hour / 3600 seconds per hour) = 2.5 seconds

**The traffic flow on a highway is measured as 2,000 vehicles per hour. If the average vehicle length is 4 meters, calculate the density of vehicles on the highway in vehicles per kilometer.**

Solution:

Density = Traffic flow / Speed

Density = 2,000 vehicles per hour / (80 km/h * 1000 m/km) = 0.025 vehicles/meter

Density in vehicles per kilometer = 0.025 vehicles/meter * 1000 meters/km = 25 vehicles/km

**The stopping sight distance required for a vehicle is 80 meters. If the initial speed of the vehicle is 100 km/h, calculate the minimum deceleration rate needed to stop the vehicle within the sight distance.**

Solution:

Speed = Initial speed = 100 km/h

Stopping sight distance = 80 meters

Deceleration rate = (Initial speed)^2 / (2 * Stopping sight distance)

Deceleration rate = (100 km/h)^2 / (2 * 80 meters) โ 125 km/h^2 โ 34.72 m/s^2

**A highway segment has a flow rate of 1,500 vehicles per hour and an average vehicle speed of 60 km/h. Calculate the density of vehicles on the highway in vehicles per kilometer.**

Solution:

Density = Traffic flow / Speed

Density = 1,500 vehicles per hour / (60 km/h * 1000 m/km) = 0.025 vehicles/meter

Density in vehicles per kilometer = 0.025 vehicles/meter * 1000 meters/km = 25 vehicles/km